標題: Titlebook: Bounded Integral Operators on L 2 Spaces; Paul Richard Halmos,Viakalathur Shankar Sunder Book 1978 Springer-Verlag Berlin Heidelberg 1978 [打印本頁] 作者: 熱情美女 時間: 2025-3-21 17:49
書目名稱Bounded Integral Operators on L 2 Spaces影響因子(影響力)
書目名稱Bounded Integral Operators on L 2 Spaces影響因子(影響力)學科排名
書目名稱Bounded Integral Operators on L 2 Spaces網(wǎng)絡公開度
書目名稱Bounded Integral Operators on L 2 Spaces網(wǎng)絡公開度學科排名
書目名稱Bounded Integral Operators on L 2 Spaces被引頻次
書目名稱Bounded Integral Operators on L 2 Spaces被引頻次學科排名
書目名稱Bounded Integral Operators on L 2 Spaces年度引用
書目名稱Bounded Integral Operators on L 2 Spaces年度引用學科排名
書目名稱Bounded Integral Operators on L 2 Spaces讀者反饋
書目名稱Bounded Integral Operators on L 2 Spaces讀者反饋學科排名
作者: 新義 時間: 2025-3-21 20:38
978-3-642-67018-3Springer-Verlag Berlin Heidelberg 1978作者: hieroglyphic 時間: 2025-3-22 04:10
Luminescence-Based Authenticity Testing,ake use of the infinite amount of room in ?., i.e., of the infinite measure. The answer is yes for II also, and the proof is not difficult, but it is better understood and more useful if instead of being attacked head on, it is embedded into a larger context.作者: CRASS 時間: 2025-3-22 05:06 作者: cardiovascular 時間: 2025-3-22 10:13
Luminescence in Electrochemistryty operator on ..(?.) (which is not an integral operator) and the tensor product of the identity operator on ..(?.) with a projection of rank 1 on ..(II) (which is an integral operator). What is the essential difference between these two kinds of examples?作者: acclimate 時間: 2025-3-22 13:46 作者: 熱心 時間: 2025-3-22 19:20
Apparatus for Bioluminescence Measurements,ad of the existential one. In precise terms: under what conditions on an operator . on ..(.) does it happen that .* is an integral operator for every unitary . on ..(.)? When it does happen, the operator . will be called a . integral operator on ..(.).作者: arsenal 時間: 2025-3-23 01:07
https://doi.org/10.1007/978-3-030-67311-6A matrix is a function. A complex . × . (rectangular) matrix, for example, is a function . from the Cartesian product {1,...,.} × {1,...,.} to the set ? of complex numbers; its value at the ordered pair <., .> is usually denoted by ... In this book it will always be denoted by the typographically and conceptually more convenient symbol .(., .).作者: TIGER 時間: 2025-3-23 05:24
Enantioselective Sensing by Luminescence,The way a matrix acts is defined by the familiar formula . The generalization to arbitrary kernels is formally obvious: . Finite sums such as the ones in (1) can always be formed; integrals such as theones indicated in (2) may fail to exist and, even when they exist, may fail todefine well-behaved functions.作者: armistice 時間: 2025-3-23 08:13
Luminescence Centers in CrystalsThe easiest examples of bounded kernels are the square-integrable ones introduced in Lemma 4.1; they induce Hilbert-Schmidt operators. The examples that follow are different; they are, for one thing, not compact.作者: FEAT 時間: 2025-3-23 12:08 作者: Palpate 時間: 2025-3-23 16:52 作者: Cerumen 時間: 2025-3-23 21:38 作者: Essential 時間: 2025-3-24 01:23 作者: reception 時間: 2025-3-24 03:24
Measure Spaces,A matrix is a function. A complex . × . (rectangular) matrix, for example, is a function . from the Cartesian product {1,...,.} × {1,...,.} to the set ? of complex numbers; its value at the ordered pair <., .> is usually denoted by ... In this book it will always be denoted by the typographically and conceptually more convenient symbol .(., .).作者: Kinetic 時間: 2025-3-24 09:25
Domains,The way a matrix acts is defined by the familiar formula . The generalization to arbitrary kernels is formally obvious: . Finite sums such as the ones in (1) can always be formed; integrals such as theones indicated in (2) may fail to exist and, even when they exist, may fail todefine well-behaved functions.作者: LEVER 時間: 2025-3-24 14:01
Examples,The easiest examples of bounded kernels are the square-integrable ones introduced in Lemma 4.1; they induce Hilbert-Schmidt operators. The examples that follow are different; they are, for one thing, not compact.作者: 輕彈 時間: 2025-3-24 17:53 作者: reception 時間: 2025-3-24 20:52
Carleman Kernels,There is a sense in which the most natural integral operators on .. are the ones induced by Carleman kernels (the semi-square-integrable kernels ., for which .(.,·)∈ ..(.) for almost every .).作者: 惹人反感 時間: 2025-3-25 00:56 作者: 惡心 時間: 2025-3-25 03:40 作者: ironic 時間: 2025-3-25 10:19 作者: Aspirin 時間: 2025-3-25 12:55 作者: Anterior 時間: 2025-3-25 19:03 作者: CRASS 時間: 2025-3-25 20:19 作者: Cerumen 時間: 2025-3-26 03:58 作者: 具體 時間: 2025-3-26 06:41
Energy transfer in concentrated systems,re cannot be one. Intuition seems to suggest that boundedness is a question of size: to be bounded is to be “small”, or in any event not too large, and every kernel that is smaller than a bounded one is itself bounded. Since kernels are complex-valued functions, “size” presumably refers to absolute 作者: ferment 時間: 2025-3-26 09:40
Luminescence in Electrochemistryty operator on ..(?.) (which is not an integral operator) and the tensor product of the identity operator on ..(?.) with a projection of rank 1 on ..(II) (which is an integral operator). What is the essential difference between these two kinds of examples?作者: 原來 時間: 2025-3-26 16:12
Luminescence of Biopolymers and Cellsators? The question refers to unitary equivalence; in precise terms, it asks for a characterization of those operators . on ..(.) for which there exists a unitary operator . on ..(.) such that .* is integral.作者: 肥料 時間: 2025-3-26 18:26
Apparatus for Bioluminescence Measurements,ad of the existential one. In precise terms: under what conditions on an operator . on ..(.) does it happen that .* is an integral operator for every unitary . on ..(.)? When it does happen, the operator . will be called a . integral operator on ..(.).作者: 動物 時間: 2025-3-27 00:29
Ferd Williams,B. Baron,S. P. Varmane that asks which operators . be integral operators (§16). The problem is one of recognition: if an integral operator on ..(.) is described in some manner other than by its kernel, how do its operatorial and measure-theoretic properties reflect the existence of a kernel that induces it? (Cf. Proble作者: Meager 時間: 2025-3-27 04:19 作者: Minatory 時間: 2025-3-27 07:21 作者: cutlery 時間: 2025-3-27 13:14
Uniqueness, to ..(.). It is natural to ask: is that linear transformation injective? In other words: is an integral operator induced by only one kernel? The content of the following assertion is that the answer is yes.作者: PRE 時間: 2025-3-27 15:42
Essential Spectrum,ty operator on ..(?.) (which is not an integral operator) and the tensor product of the identity operator on ..(?.) with a projection of rank 1 on ..(II) (which is an integral operator). What is the essential difference between these two kinds of examples?作者: diskitis 時間: 2025-3-27 19:34
Characterization,ators? The question refers to unitary equivalence; in precise terms, it asks for a characterization of those operators . on ..(.) for which there exists a unitary operator . on ..(.) such that .* is integral.作者: 表臉 時間: 2025-3-28 01:37
Universality,ad of the existential one. In precise terms: under what conditions on an operator . on ..(.) does it happen that .* is an integral operator for every unitary . on ..(.)? When it does happen, the operator . will be called a . integral operator on ..(.).作者: 舔食 時間: 2025-3-28 06:03
Book 1978an integral operator is the natural "continuous" generali- zation of the operators induced by matrices, and the only integrals that appear are the familiar Lebesgue-Stieltjes integrals on classical non-pathological mea- sure spaces. The category. Some of the flavor of the theory can be perceived in 作者: 警告 時間: 2025-3-28 07:58 作者: analogous 時間: 2025-3-28 13:30 作者: 讓你明白 時間: 2025-3-28 16:53
Ferd Williams,B. Baron,S. P. Varma not — how can the ones that are be identified? Emphasis: since the question pertains to the special category of .. spaces, not to the more abstract category of Hilbert spaces, the answer must be of the same kind. The answer cannot be expressed in unitarily invariant language, because that would imp作者: TOM 時間: 2025-3-28 20:51
Kernels,?, ?., and II. Explanation: ? is the set of all integers, ?. is the set of nonnegative integers, and ?. is the set of integers between 1 and . inclusive (. = 1, 2, 3,...); in all these cases the measure is the counting measure defined on the class of all subsets; ? is the set of all real numbers, ?.作者: MORT 時間: 2025-3-29 00:39 作者: 看法等 時間: 2025-3-29 06:29 作者: municipality 時間: 2025-3-29 09:10 作者: Alpha-Cells 時間: 2025-3-29 12:48 作者: 清真寺 時間: 2025-3-29 18:57 作者: 熔巖 時間: 2025-3-29 20:33 作者: LIEN 時間: 2025-3-30 03:42
Characterization,ators? The question refers to unitary equivalence; in precise terms, it asks for a characterization of those operators . on ..(.) for which there exists a unitary operator . on ..(.) such that .* is integral.作者: landmark 時間: 2025-3-30 04:57 作者: labile 時間: 2025-3-30 11:44 作者: 委托 時間: 2025-3-30 15:29
Kernels, is the set of nonnegative real numbers, and H is the unit interval, i.e., the set of real numbers between 0 and 1 inclusive; in all these cases the measure is Lebesgue measure defined on the class of all Borei sets. This notation (including ., ., ., and .) will be fixed throughout.作者: 固定某物 時間: 2025-3-30 17:59
Boundedness,the domain of Int .. Another possibility: a kernel may or may not be closed. (Problem 3.12 can therefore be expressed this way: is it true that if dom . is closed, then . is closed?) A notational possibility for bounded kernels (that is hereby adopted): write ‖.‖ instead of ‖Int .‖.作者: FAR 時間: 2025-3-30 22:00
Absolute Boundedness,value. These vague and heuristic comments lead to at least one specific and precise question: is it true that if . and .’ are kernels, .’ is bounded, and |.(., .)|≦|.’(., .)| almost everywhere, then . is bounded?作者: 脾氣暴躁的人 時間: 2025-3-31 04:57
Book 1978n") is sometimes defined and sometimes not. When it is defined, the definition is likely to vary from author to author. While the definition almost always involves an integral, most of its other features can vary quite considerably. Superimposed limiting operations may enter (such as L2 limits in th作者: 開花期女 時間: 2025-3-31 07:35 作者: Inclement 時間: 2025-3-31 11:41
Fluorescence Based Sensor Arrays,the domain of Int .. Another possibility: a kernel may or may not be closed. (Problem 3.12 can therefore be expressed this way: is it true that if dom . is closed, then . is closed?) A notational possibility for bounded kernels (that is hereby adopted): write ‖.‖ instead of ‖Int .‖.作者: 異端邪說下 時間: 2025-3-31 16:24
Energy transfer in concentrated systems,value. These vague and heuristic comments lead to at least one specific and precise question: is it true that if . and .’ are kernels, .’ is bounded, and |.(., .)|≦|.’(., .)| almost everywhere, then . is bounded?作者: Fillet,Filet 時間: 2025-3-31 20:30
onstruction") is sometimes defined and sometimes not. When it is defined, the definition is likely to vary from author to author. While the definition almost always involves an integral, most of its other features can vary quite considerably. Superimposed limiting operations may enter (such as L2 li作者: companion 時間: 2025-4-1 01:39
